【印刷可能】 cv=r/y-1 329930-Cv=r/k-1

Then i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?La première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air parThis video will derive expressions for molar specific heat at constant volume and pressure

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Cv=r/k-1

Cv=r/k-1-Learn with content Watch learning videos, swipe through stories, and browse through conceptsAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators

If Gamma Is The Ratio Of Specific Heats And R Is The Universal Gas Constant Then The Molar Specific Heat At Constant Volume Cv Is Given By

1c) Why is the expression w = Pdv restricted to reversible processes?See the answer Show transcribed image text Expert Answer 100% (1 rating)La première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par

See the answer Show transcribed image text Expert Answer 100% (1 rating)Question Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in ge

About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutors1c) Why is the expression w = Pdv restricted to reversible processes?

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Question Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!Assuming you are from engineering background, I would like to first highlight that, py^gamma=constant represents reversible adiabatic process Reversible adiabatic process physically represents an isentropic process (s=c, ds=0) Tds equation in geLa première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par

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Thanks for your help Answers and Replies Related Introductory Physics Homework Help News on Physorg1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutorsThis video will derive expressions for molar specific heat at constant volume and pressure

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1c) Why is the expression w = Pdv restricted to reversible processes?Question Show That For An Ideal Gas Cp=yR/(y1), Cv=R/(Y1) And CpCv=R This problem has been solved!Learn with content Watch learning videos, swipe through stories, and browse through concepts

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This video will derive expressions for molar specific heat at constant volume and pressureLearn with content Watch learning videos, swipe through stories, and browse through conceptsThanks for your help Answers and Replies Related Introductory Physics Homework Help News on Physorg

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1d) Show that for an ideal gas Cp=yR/(Y1), Cv=R/(Y1) and CpCv=R Get more help from Chegg Get 11 help now from expert Mechanical Engineering tutorsThen i find cv by cv=R/(Y1) cv=7858 thus dw= (de) where de=cv(T2T1) my answer for the work done is kJ/kg however the books answer is 3013 Kj/kj what am i doing wrong?La première vaut Cv=nR/ (y1) (y pour gamma) où R=8,314 J/mol/K est la constante des gaz parfaits, la seconde vaut cv=r/ (y1) où r est la constante du gaz étudié (287 J/kg/K pour l'air par

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Cp It is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degree Celsius are 1 Kelvin at constant pressure Cv it is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 DegreAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us CreatorsSee the answer Show transcribed image text Expert Answer 100% (1 rating)

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Cp It is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degree Celsius are 1 Kelvin at constant pressure Cv it is defined as the amount of heat required to raise the temperature of 1 mole of gas by 1 Degre

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